How many degrees is angle B in an isosceles triangle ABC if angle B is 3 times greater than angle A.

Consider two possible cases.

1) Angle B is the apex angle of this isosceles triangle.

Then the angles A and C are angles at the base of this triangle and are equal to each other.

According to the condition of the problem, angle B is 3 times greater than angle A, therefore, angles A and C are equal to B / 3 and we can draw up the following equation:

B + B / 3 + B / 3 = 180,

solving which, we get:

5V / 3 = 180,

B = 180 * 3/5;

B = 108 °.

2) Angle B is the angle at the base of this isosceles triangle.

Then the angle C should also be the angle at the base and equal to the angle B and we can make the following equation:

B + B + B / 3 = 180,

solving which, we get:

7B / 3 = 180;

B = 180 * 3/7;

B = 77 1/7 °.

Answer: angle B can be 108 ° or 77 1/7 °.