How many degrees is the water temperature at the base of the 1200-meter high waterfall higher than at its top?

Given: h (waterfall height) = 1200 m.

Reference data: g (acceleration due to gravity) = 9.81 m / s2; С (specific heat capacity of water) = 4200 J / (kg * ºС).

The temperature difference at the base of the waterfall and at the top is determined from the equality: Q1 = Q2 = C * m * Δt / (m * g * h); g * h = C * Δt and Δt = g * h / С.

Let’s calculate: Δt = 9.81 * 1200/4200 = 2.8 ºС.

Answer: The water temperature at the base of the waterfall is 2.8 ºC higher.



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