# How many degrees the temperature of water with a volume of V = 5.0 liters has changed

How many degrees the temperature of water with a volume of V = 5.0 liters has changed, if the amount of heat Q = 0.21 MJ has been released.

Quantity of heat:
Q = C * m * ∆t, where Q is the consumed heat (Q = 0.21 MJ = 210 * 10³ J), C is beats. heat capacity of water (C = 4.2 kJ / (kg * K) = 4.2 * 10³ J (kg * K)), m is the mass of water (m = ρ * V, where ρ is the density of water (ρ = 1000 kg / m³), V is the volume of water (V = 5 l = 5 dm³ = 5 * 10-³ m³)), ∆t is the change in water temperature (ºС).
Change in water temperature:
∆t = Q / (С * m) = Q / (С * ρ * V) = 210 * 10³ / (4.2 * 10³ * 1000 * 5 * 10-³) = 10 ºС.
Answer: The water temperature will change by 10 ºС.

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