How many degrees will 1 kg of gold be heated (c = 130 J / kg ° C) if it is given the same amount

How many degrees will 1 kg of gold be heated (c = 130 J / kg ° C) if it is given the same amount of heat that is required to heat 1 kg of water (c = 4200 J / kg ° C) by 1 degree?

Given: m1 (mass of gold) = 1 kg; m2 (mass of water) = 1 kg; Δt2 (preset change in water temperature) = 1 ºС.

Constants: according to the condition C1 (specific heat capacity of gold) = 130 J / (kg * ºС); С2 (specific heat capacity of water) = 4200 J / (kg * ºС).

The desired change in gold temperature can be determined from the equality: Q1 = Q2 and C1 * m1 * Δt1 = C2 * m2 * Δt2, whence Δt1 = C2 * m2 * Δt2 / (C1 * m1).

Let’s make a calculation: Δt1 = 4200 * 1 * 1 / (130 * 1) = 32.31 ºС.

Answer: Gold will heat up to 32.31 ºС.



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