How many degrees will 2 kg of hot water be cooled, giving off 504 kJ of heat to the surrounding space?

The amount of heat that water will give up to the surrounding space can be calculated using the formula:

Q = C * m * ∆t, where Q is the given amount of heat (Q = 504 kJ = 504 * 10 ^ 3 J), C is the specific heat capacity of water (C = 4200 J / (kg * K)), m is the mass water (m = 2 kg), ∆t – change in water temperature (ºС).

Let’s calculate the change in water temperature:

∆t = Q / (С * m) = 504 * 10 ^ 3 / (4200 * 2) = 504000/8400 = 60 ºС.

Answer: Having given 504 kJ of heat to the surrounding space, the water will cool down by 60 ºС.