How many degrees will 2 liters of alcohol heat up, having received 168 kJ of heat.

1. The amount of heat spent on heating the body is equal to the product of the specific heat capacity of the substance, body weight and the difference between the final and initial temperatures.
Q = c * m * (t2-t1), where c is the specific heat capacity of the substance, m is the mass of the substance, t2 and t1 are the final and initial temperatures, respectively.
Specific heat of alcohol c = 2500 J / kg * K, according to the reference book.
2. Let us write down the expression for determining the mass by specific gravity (density):
m = ρ * V, where ρ is the density of the substance, V is the volume of the substance.
The density of alcohol according to the reference book is 790 kg / m³.
3. Let us express from the formula for the amount of heat (t2-t1):
(t2-t1) = Q / (c * m)
Substitute the formula for determining the mass, and the numerical values:
(t2-t1) = Q / (c * m) = Q / (c * ρ * V) = 168000 / (2500 * 790 * 2 * 10-3) = 42.5 ° C
Answer: The alcohol will heat up to 42.5 ° C.