How many degrees will 3kg of water heat up, if all the amount of heat is produced during the combustion

How many degrees will 3kg of water heat up, if all the amount of heat is produced during the combustion of 10g of alcohol, goes to heat it?

These tasks: m1 (mass of heated water) = 3 kg; m2 (mass of alcohol consumed) = 10 g (10 * 10 ^ -3 kg).

Reference values: Cw (specific heat capacity of water) = 4200 J / (kg * K); q (specific heat of combustion of alcohol) = 2.7 * 10 ^ 7 J / kg.

We express the change in water temperature due to the combustion of alcohol from the following equality: Sv * m1 * Δt = Q = q * m2, whence Δt = q * m2 / (Sv * m1).

Calculation: Δt = 2.7 * 10 ^ 7 * 10 * 10 ^ -3 / (4200 * 3) = 21.43 ºС.

Answer: The water will heat up by 21.43 ºС.