How many degrees will 40 g of ice cool if at the same time it gives off a quantity of heat of 500 J?

Given:

m = 40 grams – ice mass;

Q = 500 Joules – the amount of heat that the ice gave away during cooling;

c = 2050 J / (kg * C) – specific heat capacity of ice.

It is required to determine dt (degree Celsius) – how many degrees the ice will cool.

Let’s convert the units of measurement of mass to the SI system:

m = 40 grams = 40 * 10-3 = 40/1000 = 0.04 kilograms.

Then, the temperature change is determined by the following formula:

dt = Q / (c * m) = 500 / (2050 * 0.04) = 500/82 = 6.1 ° Celsius (the result has been rounded to one decimal place).

Answer: The ice will cool down by 6.1 ° Celsius.