How many degrees will 50 liters of water be heated by the energy obtained from burning 1 kg of dry firewood?

Given: V (volume of heated water) = 50 l (50 * 10 ^ -3 m3); m2 (mass of burned dry wood) = 1 kg.

Constants: ρ (density of heated water) = 1000 kg / m3; С (specific heat capacity of water) = 4200 J / (kg * ºС); q (beats heat of combustion of dry wood) = 1 * 10 ^ 7 J / kg.

1) Energy from combustion of 1 kg of dry wood: Q = q * m2 = 1 * 10 ^ 7 * 1 = 10 ^ 7 J.

2) Change in temperature of 50 liters of water: Δt = Q / (C * m1) = Q / (C * ρ * V) = 10 ^ 7 / (4200 * 1000 * 50 * 10 ^ -3) = 47.6 ºС.

Answer: The temperature of 50 liters of water will increase by 47.6 ºС.