How many degrees will 510 g of copper heat up if it absorbs the same amount of heat that is released

How many degrees will 510 g of copper heat up if it absorbs the same amount of heat that is released when 2 liters are cooled? vegetable oil from 60 to 40 degrees?

Cooling grows. oils:

Q = C1 * m * (tн – tк), where С – beats. heat capacity (C1 = 1760 J / (kg * K)), m – mass (m = ρ * V; ρ = 940 kg / m3, V = 2 l = 0.002 m3), tn – initial. temperature (tн = 60 ºС), tк – end. temperature (tк = 40 ºС).

Heating copper:

Q = C2 * m * ∆t, where C2 – beats. heat capacity (C = 400 J / (K * kg)), m2 is the mass of copper (m2 = 510 g = 0.51 kg), ∆t is the temperature change.

∆t = С1 * ρ * V * (tн – tк) / (C2 * m2) = 1760 * 940 * 0.002 * (60 – 40) / (400 * 0.51) ≈ 324 ºС.