How many degrees will the temperature of 4 kg of water rise if it receives an amount of heat equal to 168 kJ?

Given: m (mass of water) = 4 kg; Q (the amount of heat received by water) = 168 kJ (168 * 10 ^ 3 J).

Constants: Sv (specific heat capacity of water) = 4200 J / (kg * K).

Solution: The calculation formula, from which the change in water temperature can be expressed, has the form: Q = Sv * m * Δt, whence Δt = Q / (Sv * m).

Let’s substitute the data into the formula: Δt = 168 * 10 ^ 3 / (4200 * 4) = 10 ºC.

Answer: The temperature of 4 kg of water will rise by 10 ºC.