How many degrees will the temperature of the water in a glass with a capacity of 200 cm3 increase

How many degrees will the temperature of the water in a glass with a capacity of 200 cm3 increase if it is given an energy of 15 J?

Data: V (capacity of a glass with water) = 200 cm3 (200 * 10-6 m3); Q (thermal energy imparted to water) = 15 J.

Constants: ρ (density of water in a glass) = 1000 kg / m3; С (specific heat capacity of water) = 4200 J / (kg * ºС).

The change in the temperature of the water in the glass is determined by the formula: Q = C * m * Δt, whence Δt = Q / (C * m) = Q / (C * ρ * V).

Calculation: Δt = 15 / (4200 * 1000 * 200 * 10-6) = 0.018 ºС.

Answer: The temperature of the water in the glass will increase by 0.018 ºС.