How many flights should be done by a car with a carrying capacity of 3 tons

How many flights should be done by a car with a carrying capacity of 3 tons to transport 10 m 3 of cement, the density of which is 2800 kg / m3.

m1 = 3 t = 3000 kg.

V1 = 10 m ^ 3.

ρ = 2800 kg / m ^ 3.

N -?

The number of machine runs N is determined by the formula: N = m / m1, where m is the mass of all cement, m1 is the mass of cement in 1 machine.

m = ρ * V, where ρ is the density of the cement, V is the volume of all cement.

N = ρ * V / m1.

N = 2800 kg / m ^ 3 * 10 m ^ 3/3000 kg = 9.3.

Since the number of flights must be an integer, then N = 10.

Answer: to transport all the cement, the car must make 10 trips.