How many g of salt is formed when 80 g of NaOH and sulfuric acid are neutralized?

univerkov | September 2, 2021 | education

Given:
m (NaOH) = 80 g

Find:
m (salt) -?

1) 2NaOH + H2SO4 => Na2SO4 + 2H2O;
2) n (NaOH) = m / M = 80/40 = 2 mol;
3) n (Na2SO4) = n (NaOH) / 2 = 2/2 = 1 mol;
4) m (Na2SO4) = n * M = 1 * 142 = 142 g.

Answer: The mass of Na2SO4 is 142 g.

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