How many g of salt will be learned from the interaction of 20 g of calcium hydroxide with sulfuric

| September 4, 2021 | education

How many g of salt will be learned from the interaction of 20 g of calcium hydroxide with sulfuric acid, the reaction yield is 75% of the theoretical?

In accordance with the condition of the problem, we write the equation:
Ca (OH) 2 + H2SO4 = CaSO4 + 2H2O – ion exchange reaction, calcium sulfate and water are released;
We calculate the molar masses of substances:
M Ca (OH) 2 = 74 g / mol;
M (CaSO4) = 136 g / mol.
We find the number of mol Ca (OH) 2, CaSO4 by the formula:
Y Ca (OH) 2 = m / M = 20/74 = 0.27 mol;
Y (CaSO4) = 0.27 mol, since the amount of substances according to the equation is 1 mol.
Determine the theoretical mass of the reaction product:
m (theoretical) CaSO4 = Y * M = 0.27 * 136 = 36.72 g.
practical mass is calculated by the formula:
W = m (practical) / m (theoretical) * 100;
m (practical) = 0b75 * 36.72 = 27.54 g.
Answer: The mass of the calcium sulfate salt is 27.54 g.



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