How many grams and how many moles of hydrochloric acid are needed to dissolve 26 grams of zinc?

To solve this problem, we write down the given: m (Zn) = 26 g
Find: m (HCl) -? v (HCl) -?
Solution:
To solve the problem, we write down the reaction equation.
Zn + HCl = ZnCl2 + H2
Let’s arrange the coefficients.
Zn + 2HCl = ZnCl2 + H2
Let’s calculate the molar masses of zinc and hydrochloric acid.
M (Zn) = 65 g / mol
M (HCl) = 1 + 35.5 = 36.5 g / mol
Over the zinc we write 26 g, and under the zinc – 65 g.
We write x g over hydrochloric acid, and 73 g under hydrochloric acid.
Let’s compose and solve the proportion:
x = 26 * 73/65 = 29.2 g
Let’s write down the formula for finding the amount of a substance.
v = m / M
Let’s substitute the data into the formula and make the calculation.
v = 29.2 / 36.5 = 0.8 mol.
Answer: 29.2 g; 0.8 mol