How many grams are 0.1 mole of sulfuric acid, how many moles are 60 grams of sodium hydroxide?

Given:
n (H2SO4) = 0.1 mol
m (NaOH) = 60 g
To find:
m (H2SO4)
n (NaOH)
Decision:
m (H2SO4) = n * M = 0.1 mol * 98 g / mol = 9.8 g
n (NaOH) = m / M = 60 g / 40 g / mol = 1.5 mol
Answer: 9.8 g; 1.5 mol



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