How many grams does 2.5 mol of nitric acid weigh?

By the formula m = M * n we get
n = 2.5 mol
Mr (HNO3) = Ar (H) + Ar (N) + Ar (O) * 3 = 1 + 14 + 16 * 3 = 63g / mol
Mr = M
m = 63g / mol + 2.5 mol = 157.5 g
Answer: 157.5 g



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