How many grams of 10% hydrochloric acid will be required to neutralize 160 g of 5% sodium hydroxide solution?

The sucrose molecule is made up of 12 carbon atoms, 22 hydrogen atoms and 11 oxygen atoms. Write down its formula and calculate the relative molecular weight.

Given: V (HCl) = 8.96 L Vm = 22.4 L / mol
Find: m solution (NaOH) -?
Decision:
Let’s write down the reaction equation NaOH + HCl => NaCl + H2O; n (HCl) = V (HCl) / Vm = 8.96 / 22.4 = 0.4 mol; n (NaOH) = n (HCl) = 0.4 mol; M (NaOH) = Mr (NaOH) = Ar (Na) * N (Na) + Ar (O) * N (O) + Ar (H) * N (H) = 23 * 1 + 16 * 1 + 1 * 1 = 40 g / mol; m (NaOH) = n (NaOH) * M (NaOH) = 0.4 * 40 = 16 g; m solution (NaOH) = m (NaOH) * 100% / ω (NaOH) = 16 * 100% / 10% = 160 g.
Answer: The mass of sodium hydroxide solution is 160 g.