How many grams of 10% sodium hydroxide solution is required to neutralize 8.96 liters of hydrochloric acid?

Given:
V (HCl) = 8.96 L
Vm = 22.4 l / mol

To find:
m solution (NaOH) -?

Decision:
1) NaOH + HCl => NaCl + H2O;
2) n (HCl) = V (HCl) / Vm = 8.96 / 22.4 = 0.4 mol;
3) n (NaOH) = n (HCl) = 0.4 mol;
4) M (NaOH) = Mr (NaOH) = Ar (Na) * N (Na) + Ar (O) * N (O) + Ar (H) * N (H) = 23 * 1 + 16 * 1 + 1 * 1 = 40 g / mol;
5) m (NaOH) = n (NaOH) * M (NaOH) = 0.4 * 40 = 16 g;
6) m solution (NaOH) = m (NaOH) * 100% / ω (NaOH) = 16 * 100% / 10% = 160 g.

Answer: The mass of sodium hydroxide solution is 160 g.