How many grams of 20% sulfuric acid and zinc will be required to produce 2.8 liters of hydrogen?

| April 2, 2021 | education

Zinc reacts violently with sulfuric acid to release hydrogen gas. At the same time, zinc sulfate (zinc sulfate) is synthesized. This reaction is described by the following equation:

Zn + H2SO4 = ZnSO4 + H2;

The metal reacts with acid in equivalent molar amounts. At the same time, the same amounts of zinc sulfate and hydrogen are synthesized.

Let’s calculate the synthesized amount of hydrogen. To do this, divide the volume of gas produced by the volume of 1 mole of gas (22.4 liters).

M H2 = 2 grams / mol; N H2 = 2.8 / 22.4 = 0.125 mol;

The same amount of zinc and sulfuric acid will react.

Let’s calculate the weight of zinc.

M Zn = 65 grams / mol; m Zn = 0.125 x 65 = 8.125 grams;

Let’s calculate the weight of the acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol; m H2SO4 = 0.125 x 98 = 12.25 grams;

The weight of a 20% acid solution will be 12.25 / 0.2 = 61.25 grams.



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