How many grams of 23% nitric acid solution will be used to neutralize 80 grams of solution with a mass fraction of (NaOH) -30%.

Given:
w (HNO3) = 23% = 0.23
m solution (NaOH) = 80 g
w (NaOH) = 30% = 0.3
To find:
m solution (HNO3)
Decision:
HNO3 + NaOH = NaNO3 + H2O
m in-islands (NaOH) = w * m solution = 0.3 * 80 g = 24 g
n (NaOH) = m / M = 24 g / 40 g / mol = 0.6 mol
n (NaOH): n (HNO3) = 1: 1
n (HNO3) = 0.6 mol
m in islands (HNO3) = n * M = 0.6 mol * 63 g / mol = 37.8 g
m solution (HNO3) = m in-va / w = 37.8 g / 0.23 = 164 g
Answer: 164 g