How many grams of 60% sulfuric acid solution can be prepared if sulfuric acid is added to 0.16 kg of water?

W (H2SO4) = 60%.
m (H2O) = 0.16 kg.
Determine the mass of the sulfuric acid solution. We write down the solution.
We use the following formula.
W = m r.v. / m r-ra * 100%.
m solution = m r.v. + m H2O.
Let’s denote the solute (or the mass of sulfuric acid) through x. We write down the resulting reaction equation.
60 = x / x + 160 * 100 100x / x + 160 = 60100x = 60 * (x + 160) 100x = 60x + 9600100x – 60x = 960040x = 9600X = 9600: 40 = 240 g or 0.24 kg.
This means that the mass of sulfuric acid is 0.24 kg.
We find the mass of the solution.
m solution = 0.24 + 0.16 = 0.4 kg.
Answer: the mass of 60 sulfuric acid solution is 0.4 kilograms.