How many grams of a 15% solution can be prepared from 300 grams of sodium chloride?

How many grams of a 15% solution can be prepared from 300 grams of sodium chloride? how much water is required for this?

Given:
ω (NaCl) = 15%
m (NaCl) = 300 g

To find:
m solution (NaCl) -?
m (H2O) -?

Decision:
1) Calculate the mass of the sodium chloride solution:
m solution (NaCl) = m (NaCl) * 100% / ω (NaCl) = 300 * 100% / 15% = 2000 g;
2) Calculate the mass of water:
m (H2O) = m solution (NaCl) – m (NaCl) = 2000 – 300 = 1700 g.

Answer: The mass of the NaCl solution is 2000 g; H2O – 1700