How many grams of acetaldehyde can be obtained from 56 liters of acetylene by Kucherov’s

How many grams of acetaldehyde can be obtained from 56 liters of acetylene by Kucherov’s reaction, if the yield is 70% of the theoretical?

To solve, we write down the equation of the process:

С2Н2 + Н2О = Н2С = СНОН (vinyl alcohol) = СН3 – СОН – hydration, acetaldehyde is released;
Calculations by formulas:
M (C2H2) = 26 g / mol;

M (C2H4O) = 44 g / mol.

3. Proportion:

1 mol of gas at normal level – 22.4 liters;

X mol (C2H2) – 56 liters from here, X mol (C2H2) = 1 * 56 / 22.4 = 2.5 mol.

Y (C2H4O) = 2.5 mol since the amount of substances is 1 mol.

We find the mass of the aldehyde taking into account the product yield:
m (C2H4O) = Y * M = 2.5 * 44 = 110 g (theoretical weight);

m (C2H4O) = 110 * 0.70 = 77 g (practical weight).

Answer: the mass of acetaldehyde is 77 g