How many grams of acetic acid are formed when 2.5 moles of sodium acetate react with sulfuric acid?

Let’s carry out the solution by composing the reaction equation:
2CH3COONa + H2SO4 = 2CH3COOH + Na2SO4 – exchange reaction, acetic acid was obtained;
Let’s write the proportion using these equations:
2.5 mol (CH3COONa) – X mol (CH3COOH);
-2 mol -2 mol hence, X mol (CH3COOH) = 2.5 * 2/2 = 2.5 mol;
Let’s determine the mass of the reaction product:
M (CH3COOH) = 12 * 2 + 4 + 16 * 2 = 60 g / mol;
m (CH3COOH) = Y * M = 2.5 * 60 = 150 g.
Answer: during the reaction, acetic acid with a mass of 150 g was obtained.