How many grams of acetic acid are needed for the esterification reaction if 118.8 g

| June 25, 2021 | education

How many grams of acetic acid are needed for the esterification reaction if 118.8 g of ethyl acetate are extracted; mass fraction of the output is 90%?

We carry out the solution:
1. We write down the equation according to the problem statement:
CH3COOH + C2H5OH = CH3COO – C2H5 + H2O – esterification reaction, ethyl acetate ester was obtained;
2. Calculation of molar masses of organic substances:
M (CH3COOH) = 60 g / mol;
M (ether) = 112 g / mol.
3. Find the theoretical mass of the ether:
m (ether) = m (practical) / W = 118.8 / 0.90 = 132 g.
4. Determine the amount of ether moles:
Y (ether) = m / M = 132/112 = 1.18 mol;
Y (CH3COOH) = 1.18 mol since the amount of these substances according to the equation is 1 mol.
5. We calculate the mass of acetic acid:
m (CH3COOH) = Y * M = 1.18 * 60 = 70.8 g.
Answer: to carry out the esterification reaction, acetic acid with a mass of 70.8 g is required.



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