How many grams of aluminum can be obtained by reducing 102g of al2o3 with coal?

Let’s execute the solution:
2Al2O3 + 3C = 4Al + 3CO2 – ОВР, aluminum was obtained in the process of reduction of aluminum oxide with coal;
Let’s calculate the molar masses of substances:
M (Al2O3) = 101.8 g / mol;
M (Al) = 26.9 g / mol.
Determine the number of moles:
Y (Al2O3) = m / M = 102 / 101.8 = 1 mol.
The proportion shows:
1 mol (Al2O3) – X mol (Al);
-2 mol – 4 mol from here, X mol (Al) = 1 * 4/2 = 2 mol.
Find the mass of aluminum:
m (Al) = Y * M = 2 * 26.9 = 53.8 g.
Answer: the mass of aluminum is 53.8 g.