How many grams of aluminum oxide is formed by the interaction of 5.4 grams of aluminum with 3x voluntary iron oxides.

univerkov | December 8, 2020 | education

2Al + Fe2O3 = Al2O3 + 2Fe
M (Al) = 27 g / mol
n (Al) = 5.4 / 27 = 0.2 mol
n (Al2O3) = 0.2 / 2 = 0.1 mol
M (Al2O3) = 102 g / mol
m (Al2O3) = 102 х0.1 = 10.2 grams

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