How many grams of aluminum oxide will react with 300 g of 25% hydrochloric acid solution ..

1.Let’s find the mass of HCl in the solution.

W = m (substance): m (solution) × 100%, hence

m (substance) = (m (solution) × W): 100%.

m (substance) = (300 g × 25%): 100% = 75 g.

2.Let’s find the amount of substance HCl.

М (НCl) = 36.5 g / mol.

n = 75 g: 36.5 g / mol = 2.05 mol.

Let’s find the quantitative ratios of substances.

6HCl + Al2O3 = 2AlCl3 + 3H2O.

For 6 mol of HCl, there is 1 mol of Al2O3.

The substances are in quantitative ratios of 6: 1.

The amount of Al2O3 is 6 times less than the amount of HCl.

n (Al2O3) = 1/6 n (HCl) = 2.05: 6 = 0.34 mol.

3.Let’s find the mass of Al2O3.

m = nM.

M (Al2O3) = 102 g / mol.

m = 0.34 mol × 102 g / mol = 34.68 g.

Answer: 34.68 g.