# How many grams of aluminum should be taken for the reaction with hydrochloric acid

January 30, 2021 | education

| **How many grams of aluminum should be taken for the reaction with hydrochloric acid, so that the volume of hydrogen released is 336 liters.**

Aluminum reacts with hydrochloric acid. This forms an aluminum chloride salt and releases hydrogen gas. The interaction is described by the following chemical equation.

Al + 3HCl = AlCl3 + 3/2 H2;

Let’s find the chemical amount of the evolved hydrogen gas.

For this purpose, we find the ratio of its volume to the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).

N H2 = 336 / 22.4 = 15 mol;

To obtain such an amount of hydrogen, it is necessary to dissolve 0.96 x 2/3 = 0.64 mol of aluminum.

Let’s calculate its mass.

M Al = 27 grams / mol;

m Al = 27 x 15 = 405 grams;

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