How many grams of aluminum should be taken for the reaction with hydrochloric acid

How many grams of aluminum should be taken for the reaction with hydrochloric acid, so that the volume of hydrogen released is 336 liters.

Aluminum reacts with hydrochloric acid. This forms an aluminum chloride salt and releases hydrogen gas. The interaction is described by the following chemical equation.

Al + 3HCl = AlCl3 + 3/2 H2;

Let’s find the chemical amount of the evolved hydrogen gas.

For this purpose, we find the ratio of its volume to the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).

N H2 = 336 / 22.4 = 15 mol;

To obtain such an amount of hydrogen, it is necessary to dissolve 0.96 x 2/3 = 0.64 mol of aluminum.

Let’s calculate its mass.

M Al = 27 grams / mol;

m Al = 27 x 15 = 405 grams;