How many grams of benzene reacted with chlorine if 337 ml of hydrogen chloride were released.

Let’s implement the solution:
1. Let’s write the equation:
С6Н6 + Сl2 = C6H5Cl + HCl – substitutions, benzene chloride was obtained;
Let’s convert the units of volume to liters:
1 L – 1000 ml, so V (C6H5Cl) = 0.337 L;
Determine the number of moles of the reaction product – С6Н5Cl;
1 mol of gas at normal level – 22.4 l;
X mol (С6Н5Cl) – 0.337 L. hence, X mol (C6H5Cl) = 1 * 0.337 / 22.4 = 0.015 mol;
Y (C6H6) = 0.015 mol since the amount of these substances according to the equation is 1 mol.
We find the mass of benzene by the formula:
m (C6H6) = Y * M = 0.015 * 78 = 1.173 g.
Answer: the mass of benzene required for chlorination is 1.173 g.