How many grams of benzene will be obtained from 11.2 liters of acetylene?

To solve, we write the equation:
3C2H2 = C6H6 – the trimerization reaction occurs on a hot carbon catalyst, benzene is obtained;
Calculating molar mass:
M (C6H6) = 78 g / mol.
Let’s make a proportion according to the equation:
1 mol of gas at normal level – 22.4 liters;
X mol (C2H2) – 11.2 liters. hence, X mol (C2H2) = 1 * 11.2 / 22.4 = 0.5 mol.
Determine the number of moles of benzene:
0.5 mol (C2H2) – X mol (C6H6);
-3 mol – 1 mol from here, X mol (C6H6) = 0.5 * 1/3 = 0.16 mol.
We find the mass of benzene by the formula:
m (C6H6) = Y * M = 0.16 * 78 = 12.48 g.
Answer: the mass of benzene is 12.48 g.