How many grams of bromine can add to 2.8 liters of ethylene?

Decision:
n – amount of substance
C2H4 – ethylene formula
n (C2H4) = 2.8 L: 22.4 L / mol = 0.125 mol
n (C2H4) = n (Br2)
It turns out 0.125 mol (according to the equation)
m (Br2) = 0.125 * 160 = 20g
Answer: 20g bromine



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