How many grams of calcium and oxygen will react to form 168 g of calcium oxide?

Calcium enters into an oxidation reaction with oxygen. This reaction is described by the following equation:

Ca + ½ O2 = CaO;

During oxidation, one oxygen atom is attached to the calcium atom. In this case, one molecule of calcium oxide is synthesized.

Let’s determine the chemical (molar) amount of calcium oxide.

To do this, divide the available weight of calcium by the weight of 1 mole of this substance.

M CaO = 40 + 16 = 56 grams / mol; N CaO = 168/56 = 3 mol;

To synthesize such an amount of calcium oxide, it is necessary to take the same amount of calcium.

Let’s find its mass.

N Ca = 3 mol; M Ca = 40 grams / mol; m Ca = 3 x 40 = 120 grams;

To synthesize such an amount of calcium oxide, it is necessary to take half the amount of oxygen.

Let’s calculate its weight.

N O2 = 3/2 = 1.5 mol; M O2 = 32 grams / mol; m O2 = 1.5 x 32 = 48 grams;