How many grams of Calcium (Ca) was burned if 44.8 liters of O2 (oxygen) were consumed?

univerkov | November 30, 2020 | education

find the amount of mole of oxygen
n (o2) = 44.8 \ 22.4 = 2 mol
according to the equation 2Ca + O2 = 2CaO, the amount of calcium substance is twice as much then n (Ca) = 2 * 2 = 4 mol
m (Ca) = 4 * 40 = 160g

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