How many grams of calcium carbide is needed to obtain 4.48 liters of acetylene?

Acetylene is synthesized by the interaction of calcium carbide with water.

CaC2 + 2H2O = Ca (OH) 2 + C2H2 ↑;

Let’s determine the molar amount of acetylene.

To do this, we divide its volume by the volume of 1 mole of gas under normal conditions (it is 22.4 liters).

N C2H2 = 4.48 / 22.4 = 0.2 mol;

To get this amount of acetylene, you need to take the same amount of calcium carbide. Let’s find its weight.

For this purpose, we multiply the molar amount of the substance by the weight of 1 mole of the substance, which is equal to the sum of the molar weights of the elements constituting this molecule.

M CaC2 = 40 + 12 x 2 = 64 grams / mol;

m CaC2 = 0.2 x 64 = 18.8 grams;