How many grams of calcium carbonate is formed when 250 g of calcium hydroxide interacts with carbon dioxide?

To solve, we write down the equation of the process:

m = 250 g X g -?

Ca (OH) 2 + CO2 = CaCO3 + H2O – ion exchange, precipitate of calcium carbonate is precipitated;
Let’s make the calculations:
M Ca (OH) 2 = 74 g / mol;

M (CaCO3) = 100 g / mol;

Y Ca (OH) 2 = m / M = 250/74 = 3.38 mol;

Y (CaCO3) = 3.38 mol since the amount of substances is 1 mol.

3. Find the mass of the sediment:

m (CaCO3) = Y * M = 3.38 * 100 = 338 g

Answer: Received calcium carbonate weighing 338 g