How many grams of calcium carbonate is formed when 42 g of calcium oxide reacts with 44 g of carbon dioxide?

1) Let’s compose the reaction equation CaO + Co2 ==> CaCO3
2) Determine the amount of substance of the starting materials n (CaO) = m (CaO) * M (CaO) = 42 g * 56 g / mol = 2352 mol n (CO2) = m (CO2) * M (CO2) = 44 g * 44 g / mol = 1936 mol
3) Based on the lack of the starting material (CO2), we determine the mass of calcium carbonate 44 g (CO2) ==> 44 g / mol (CO2) x g (CaCO3) ==> 100 g / mol (CaCO3) therefore: m (CaCO3) = 100 g / mol * 44 g / 44 g / mol = 100 g
Answer: m (CaCO3) = 100 g