How many grams of calcium hydroxide can be obtained by reacting its oxide with water, obtained by decomposition

How many grams of calcium hydroxide can be obtained by reacting its oxide with water, obtained by decomposition of 10 g of calcium carbonate. The resulting calcium hydroxide reacts with nitric acid. How much salt is formed after neutralization and how many liters of oxygen can be obtained from the decomposition of the resulting calcium nitrate?

Given:
m (CaCO3) = 10 g

To find:
m (Ca (OH) 2) -?
m (salt) -?
V (O2) -?

Decision:
1) CaCO3 => CaO + CO2;
2) n (CaCO3) = m / M = 10/100 = 0.1 mol;
3) n (CaO) = n (CaCO3) = 0.1 mol;
4) CaO + H2O => Ca (OH) 2;
5) n (Ca (OH) 2) = n (CaO) = 0.1 mol;
6) m (Ca (OH) 2) = n * M = 0.1 * 74 = 7.4 g;
7) Ca (OH) 2 + 2HNO3 => Ca (NO3) 2 + 2H2O;
8) n (Ca (NO3) 2) = n (Ca (OH) 2) = 0.1 mol;
9) m (Ca (NO3) 2) = n * M = 0.1 * 164 = 16.4 g;
10) Ca (NO3) 2 => Ca (NO2) 2 + O2;
11) n (O2) = n (Ca (NO3) 2) = 0.1 mol;
12) V (O2) = n * Vm = 0.1 * 22.4 = 2.24 liters.

Answer: The mass of Ca (OH) 2 is 7.4 g; Ca (NO3) 2 – 16.4 g; O2 volume – 2.24 l.