How many grams of calcium oxide is formed by the interaction of calcium with oxygen with a volume of 11.2 liters.

We will execute the solution step by step:
1. Let’s write down the reaction equation:
2Ca + O2 = 2CaO – the reaction of the compound, calcium oxide is obtained;
2. Determine the molecular weight of calcium oxide:
M (CaO) = 40 + 16 = 56 g / mol;
3. Let’s calculate the number of O2 moles according to Avogadro’s law:
1 mol gaseous in-va – 22.4 liters. at n. at
X mol (O2) – -11.2 liters. hence, X mol (O2) = 1 * 11.2 / 22.4 = 0.5 mol;
4. Let’s make the proportion according to the equation:
0.5 mol (O2) – X mol (CaO);
-1 mol – 2 mol hence, X mol (CaO) = 0.5 * 2/1 = 1 mol;
5. Let’s calculate the mass of calcium oxide by the formula:
M (CaO) = 1 * 56 = 56 g.
Answer: in the course of the reaction, calcium oxide with a mass of 56 g was formed.