How many grams of calcium oxide is formed when 500 grams of calcium carbonate containing 20% impurities is decomposed?

univerkov | January 17, 2021 | education

Given:
m s (CaCO3) = 500 g
w p (CaCO3) = 20%
To find:
m (CaO)
Decision:
CaCO3 = CaO + CO2
w h.h. (CaCO3) = 100% -20% = 80% = 0.8
m in (CaCO3) = w h.v * m s = 0.8 * 500 g = 400 g
n (CaCO3) = m / M = 400 g / 100 g / mol = 4 mol
n (CaCO3): n (CaO) = 1:

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