# How many grams of calcium phosphate is formed during the neutralization reaction of calcium

How many grams of calcium phosphate is formed during the neutralization reaction of calcium hydroxide weighing 7.4 g?

Let’s implement the solution:
1. Let us write the equation according to the problem statement:
m = 7.4 g. X g -?
Ca (OH) 2 + H2SO4 = CaSO4 + 2H2O – ion exchange reaction, obtained a precipitate of calcium sulfate, water;
2. Let’s calculate the molar masses of inorganic substances:
M Ca (OH) 2 = 74 g / mol;
M (CaSO4) = 136 g / mol.
3. Calculate the number of moles of the starting material, if the mass is known:
Y Ca (OH) 2 = m / M = 7.4 / 74 = 0.1 mol;
Y CaSO4 = 0.1 mol since the amount of these substances according to the equation is 1 mol.
4. Find the mass of salt:
m (CaSO4) = Y * M = 0.1 * 136 = 13.6 g.
Answer: during the reaction, calcium sulfate with a mass of 13.6 g was obtained.

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