How many grams of carbon dioxide is generated by burning 67.2 liters of propane?

The propane oxidation reaction is described by the following chemical reaction equation.

C3H8 + 5O2 = 3CO2 + 4H2O;

According to the coefficients of this equation, 5 oxygen molecules are required to oxidize 1 propane molecule. This synthesizes 3 molecules of carbon dioxide.

Let’s calculate the amount of propane available.

To do this, we divide the available gas volume by the volume of 1 mole of ideal gas under normal conditions.

N C3H8 = 67.2 / 22.4 = 3 mol;

The amount of carbon dioxide will be.

N CO2 = 3 x 3 = 9 mol;

Let’s calculate the weight of the gas. To do this, multiply the amount of substance by the weight of 1 mole of gas.

M CO2 = 12 + 16 x 2 = 44 grams / mol;

m CO2 = 9 x 44 = 396 grams;