How many grams of carbonic acid was formed by the interaction of 10 g of limestone containing 5% impurities with hydrochloric acid?

limestone formula CaCO3
CaCO3 + 2HCl = H2CO3 + CaCl
in general, according to the rules, the reaction should be written like this:
CaCO3 + 2HCl = CO2 + H2O + CaCl2
since carbonic acid decomposes immediately
but if you are asked to find its mass ..
mass of pure limestone = 10 * 0.95 = 9.5 grams
n (CaCO3) 9.5 / 100 = 0.095 mol
n (h2co3) = 0.095
m (h2co3) = 0.095 * (2 + 12 + 16 * 3) = 5.89
Answer: 5.89