How many grams of chlorine is required to interact with 5.4 g aluminum?

The reaction of aluminum with chlorine is described by the following chemical equation:

2Al + 3Cl2 = 2AlCl3;

That is, three moles of chlorine react with two moles of aluminum.

Let us determine the molar amount of aluminum weighing 5.4 grams.

The molar mass of aluminum is 27 grams / mol.

This mass contains 5.4 / 27 = 0.2 mol.

For a reaction with such an amount of aluminum, you need 0.2 x 3/2 = 0.3 mol of chlorine.

Let’s find the mass of this amount of chlorine.

Its molar mass is 35.5 x 2 = 71 grams / mol.

The chlorine mass will be 0.3 x 71 = 21.3 grams.