How many grams of coal burned out if 22 g of carbon dioxide were formed.

1.Let’s find the amount of substance CO2.

M (CO2) = 44 g / mol.

n = 22 g: 44 g / mol = 0.5 mol.

2. Let’s compose the reaction equation, find the quantitative ratios of substances.

C + O2 = CO2

For 1 mol of C, there is 1 mol of CO2.

The substances are in quantitative ratios of 1: 1.

The amount of substance is equal.

n (CO2) = n (C) = 0.5 mol.

3.Let’s find the mass of coal C.

m = nM.

M (C) = 12 g / mol.

m = 0.5 mol × 12 g / mol = 6 gr.

Answer: 6 gr.