How many grams of copper chloride is formed by the interaction of 25 g of copper (2) oxide with hydrochloric

How many grams of copper chloride is formed by the interaction of 25 g of copper (2) oxide with hydrochloric acid. It is given to find a solution with the formulas.

Let’s execute the solution:

According to the condition of the problem, we will write the data:
m = 25 g X g -?

CuO + 2HCl = CuCl2 + H2O – ion exchange, copper chloride is released;

Calculations according to the formulas of substances:
M (CuO) = 79.5 g / mol;

M (CuCl2) = 134.5 g / mol.

Determine the amount of the original substance:
Y (CuO) = m / M = 25 / 79.5 = 0.3 mol;

Y (CuCl2) = 0.3 mol since the amount of substances is 1 mol.

Find the mass of salt:
m (CuCl2) = Y * M = 0.3 * 134.5 = 40.35 g

Answer: received copper chloride weighing 40.35 g