How many grams of copper hydroxide is formed when 112g of 20% potassium hydroxide solution

How many grams of copper hydroxide is formed when 112g of 20% potassium hydroxide solution interacts with copper chloride?

In order to find how many grams of copper hydroxide is formed by the interaction of 112 grams of a 20% potassium hydroxide solution with copper chloride, we will compose and solve the proportion.

We’ll start by writing down the reaction equation:

KOH + CuCl2 = Cu (OH) 2 + 2KCl;

equalize the reaction equation:

2KOH + CuCl2 = Cu (OH) 2 + 2KCl;

m (KOH) = 112 * 20/100 = 22.4 grams.

n = m / M;

M (KOH) = 39 + 16 + 1 = 56;

n (KOH) = 112/56 = 2 mol.

2 mol = 1 mol 2 mol = x mol. x = 1 mol.

m = M * n;

M (CuOH) = 64 + 16 + 1 = 81;

m (CuOH) = 81 * 1 = 81 grams.