How many grams of copper (II) oxide can be reduced using 2.24L hydrogen?

Copper oxide is reduced with hydrogen gas. During the reaction, metallic copper and water are synthesized. The reaction is described by the following chemical reaction equation:

CuO + H2 = Cu + H2O;

Cupric oxide reacts with hydrogen in equal (equivalent) molar amounts. When the reaction proceeds, the same equal chemical amounts of metallic copper and water are synthesized.

Find the chemical amount of hydrogen gas.

For this purpose, we divide its volume by the volume of 1 mole of gas (which is 22.4 liters).

V H2 = 2.24 liters;

N H2 = 2.24 / 22.4 = 0.1 mol;

We calculate the weight of 0.1 mol of copper oxide.

M CuO = 64 + 16 = 80 grams / mol;

m CuO = 0.1 x 80 = 8 grams;